UVA 1207 Solution -AGTC

/* Solved by using Edit-Distance Algorithm*/

/*
uva id- shoaib05
Accpted Time: 0.001
*/

#include<stdio.h>
#include<algorithm>
#include<iostream>

using namespace std;

char x[5010],y[5010];
int len1,len2,table[5010][5010];

void buildTable()
{
int i,j;
for(i=0;i<=len1;i++)
table[i][0]=i;
for(j=0;j<=len2;j++)
table[0][j]=j;
for(i=1;i<=len1;i++)
{
for(j=1;j<=len2;j++)
{
if(x[i-1]==y[j-1])
table[i][j]=table[i-1][j-1];
else
table[i][j]=min(table[i-1][j-1],min(table[i-1][j],table[i][j-1]))+1;
}
}
}


int main()
{
while(scanf("%d %s %d %s",&len1,x,&len2,y)==4)
{
buildTable();
printf("%d\n",table[len1][len2]);
}
return 0;
}

Comments

Post a Comment

Popular posts from this blog

uva 679 - Dropping Balls Solution

uva 679 - Dropping Balls Solution Algorithm: 1. convert (position-1)  to binary and store it to a string. 2. make the binary string length equal to the (depth-1) by adding zero(0) at start of the string. 3. reverse the binary string. 4. convert binary string to integer + power(2,depth-1). Example: depth=7; position=4; covert 4-1= 3 to binary. binary string is 11. make the string length 7-1=6 by adding 0. Updated string 000011. reverse the binary string and string is now 110000 convert binary string(110000) to integer. value is 48. calculate power_value=pow(2,7-1)=pow(2,6)=64. Answer is = 48 + 64=112. Code in C++: #include<iostream> #include<string> #include<algorithm> using namespace std; string convertDecimalToBinary(int num){ string result; while(num!=0){ if(num%2==1) result.insert(0,1,'1'); else result.insert(0,1,'0'); num=num/2; } return result; } int convertBinaryToDecimal(string &n...
Read more

uva 481 - What Goes Up Solution

uva 481 - What Goes Up Solution #include<iostream> #include<vector> using namespace std; void binary_search(int *arr, int search_value, int start, int end, int &index){ if (start == end){ index = start; return; } int mid = (start + end) / 2; if (arr[mid] == search_value){ index = mid; return; } else if (arr[mid + 1] == search_value){ index = mid + 1; return; } else if (arr[mid]<search_value && arr[mid + 1]>search_value){ index = mid + 1; return; } else if (arr[mid] > search_value){ binary_search(arr, search_value, start, mid, index); } else{ binary_search(arr, search_value, mid + 1, end, index); } } void calculate_lis(vector<int>&arr,vector<int>&result){ int *temp, i, max = 0, j, index, n = arr.size(), *res; temp = new int[n]; res = new int[n]; temp[0] = 0; for (i = 1; i < n; i++){ if (arr[temp[max]] < arr[i]){ res[i] = temp[max]; max++; ...
Read more

uva-10077 Solution --- The Stern-Brocot Number System

#include<iostream> using namespace std; int main(){ int input_num,input_den,left_num,left_den,right_num,right_den,cur_num,cur_den; while(cin>>input_num>>input_den){ if(input_num==1 && input_den==1) break; left_num=0; left_den=1; right_num=1; right_den=0; cur_num=cur_den=1; while(true){ if(cur_num== input_num && cur_den==input_den) break; if(cur_num*input_den < cur_den*input_num){ cout<<"R"; left_num=cur_num; left_den=cur_den; cur_num+=right_num; cur_den+=right_den; }else{ cout<<"L"; right_num=cur_num; right_den=cur_den; cur_num+=left_num; cur_den+=left_den; } } cout<<endl; } return 0; }
Read more